e = 2 7r/n$ sin r the instantaneous generated e.m.f.Why this is not rendered automatically
This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
Routes equations where Steinmetz turns alternating quantities into symbolic algebra.
candidate records in this family.
reviewable relation candidates.
sources represented.
These are OCR candidates. They remain plain text until a reviewer checks the scan and promotes the formula into a curated math page.
e = 2 7r/n$ sin r the instantaneous generated e.m.f.This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
B = 6’ + jh” = 6(cos 13 + j sin /3)This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
is r - j (x -f x0} = r = .6, x + x0 = 0, and tan S>0 = 0 ;This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
is r - j {x + Xo) = r = 0.6, x -{- Xo = 0, and tan do = 0; thatThis line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
= - J = (tan a - j) (7)This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
If an alternating current i = I0 sin 6 passes through a resist-This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
1.) Ohm’s law : i = e j r, where r, the resistance, is aThis line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
1.) Ohm’s law : i = e j r, where r, the resistance, is aThis line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
or, if E = e -\-je’ is the impressed E.M.F., and 7 = i ’ -\- ji’This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
/, upon the e.m.f., or by IE cos d, where 9 = angle of time-This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
but E = E^y I^E^j z. If x^ > - 2,t-, it raises, if ;r < - 2 jr,This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
a maximum for dP^j db = 0, that is, according to § 61, if -This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
e.m.f., e = EQ sin 6.This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
at A and is tan C02 = Vijv^ (thus being greater) when theThis line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
R = j/VK. (15)This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
copper of No. 5, or j of ;j = ^: Cu. = ^This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
FH = DH sin a, and DL = DH sin av (1)This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
cubic hyperbolas: e^i = kz2; or, el =- £j and since we find forThis line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
fc1 = 2 TT / sin <t>dfa (3)This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
cos r = - - - - = 0.4This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
iron is /z4 = 280 at B4 = 2850. Thus the field intensity/ H = - jThis line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
e = 2 irfn$ sin 2 IT} (t - ti)This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
or, e = 2-jrfn& sin (6 - 0i),This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
i*r = 702r sin2 0 = ^r C1 ~ cos 2 0),This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
e = E0 sin (0 - 0i) = 273 sin (0 - 0i) ;This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
e = 273 sin 210 (t - h).This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
e = - -j-. L 108 absolute unitsThis line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
34. An alternating current i = IQ sin 2irft or i - I0 sin 0This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
i = /0 sin 2 IT/ (t - t’),This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
i = IQ sin 6 passes through a circuit of resistance r and induc-This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
2 irft = /o sin 0) of effective valueThis line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
e’2 = - xI0 cos 2 irft = - xIQ cos 6,This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
e’z = - xIQ cos 0,This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
ty : i = 7i sin 2 TT N(t - A) + 7, sin 6 TT N (t - /3)This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
i = 1 sin 2 -wjl,This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
/ = / sin =^ (/ - A) = /sin 2 tt A” (/ - A) ;This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
and i = I cos 2 tt/^.This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
i = /1 sin 2-KJ{t - ti) + h sin 4 7r/(i - ^2)This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
i = Ai sin 2 tt/^ + A2 sin 4 x// + A3 sin 6 tt/^ + …This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
i = 7] sin 2 Trf(t - ti) + 1 3 sin 6 Trf(t - ts)This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
i = A\ sin 2Tvft + A3 sin 6x/f + ^5 sin lOvr/^ + …This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
i = Ai sin 2 vNt + A, sin 4 ttNI + A, sin C irNl + …This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
E0 = V(^ cos w + Ir)2 -f- (E sin w + Ix)z.This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
Thus, for instance, at the amplitude AOB^ == </>j = 2ir/j/ T’This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
i = I cos (?> - ??2),This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
i = / cos (?? - /3)This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
e = E cos (i? 4- a’) -This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
i = I cos {t} + /3’)This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
i = I cos (?? - /3)This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
ffo = Vfr2 + S^2 + 20^ sin Wi,This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
since y’2 = - 1, j = V- 1 ;This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
Ea = V{E COS 6 4- /r)2 + (E sin 6 + Ixy.This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
100 volts, and /j = 75 amperes, for a non-inductive secon-This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
- /V) , tan w0 =This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
$Fo = V^H^i’ + 2 IFSFi sin Wi ,This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
h = 7 sin ^ is the vertical component of the sine wave.This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
j’ = - 1,This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
system of ordinary numbers, this definition of j = V - 1 doesThis line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
I = {a + a’) +j(6 + 6’).This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
or e.o = \/(e + ir)- + {ix^, tan ^o = - 77^-This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
0 = 0’+ jc” = c(cos T + j sin 7)This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
^ = -[cos (a + |3 - 7) + j sin (a + |8 - 7)],This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
c = OC cos (0 - 0o).This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
Z -jx0 = r-j(x +#e).This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
i = I cos’ (?9 - 0)This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
circuit •- z= 1 Qj r = 1>0> x= 0 (Curve j)This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
&Q = ro JXoi ZQ = V f0 -j- Xo ,This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
is r - y (.r + ;r^) = r = .6, x + x^ = 0, and tan w^ = ;This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
X = .9, X = Oy X = - .9, and Z^ = .3 -j .4.This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
this case, a = ::^j 2 r,,, while in a continuous-current circuitThis line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
Zo = r„+ j”j:0 =0.1 +0.3j;This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.
Assuming tan a = 0.6, which is a fair value for a closed mag-This line is OCR/PDF-derived candidate text. Treat it as a pointer to the source scan, not as a verified mathematical transcription.